challenges/e1.hs

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Haskell
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divisors_3_5 [] acc = acc
divisors_3_5 (x:xs) acc
| rem x 3 == 0 || rem x 5 == 0 = divisors_3_5 xs (x:acc)
| otherwise = divisors_3_5 xs acc
e1 = sum (divisors_3_5 [1 .. 999] [])